ORIFICE IN THE SIDE OF A VESSEL. lf>5 



Q = I -V%g (h 7-4 x) Vhi + xdx 



which agrees with (?). 



COR. 5. If the base coincides with the surface of the 

 liquid, h l = 0, and (11) becomes 



Q = ^mVzgh, 



which agrees with (3). 



(3) When the orifice is a triangle whose vertex? is 

 upwards and base horizontal. 



Here 2y = - x, 



which in (9), between the same limits, x = and x = 

 li h t , gives 



which agrees with (8). 



COK. 6. If the vertex coincides with the surface of the 

 liquid, /*! =0, and (12) becomes 



Q = IbhVfyh, 

 which agrees with (1). 



Cor. 7. From Cors. 5 and 6 we see that the quantities 

 discharged in the same time through two equal triangular 

 orifices in the side of a vessel kept constantly full, the one 

 having its base and the other its vertex upwards in the sur- 

 face of the liquid, are in the ratio of 2 : 3. 



