ALTERNATING-CURRENT TRANSFORMER. 



= 0.455, and the ordinate of 2 being equal to 174* X 2 -r- no = 5.5 

 amp. 



Oi; O2, represent directly the primary currents. 



To find the secondary currents I have redrawn the same diagram 

 in Fig. 45. O A is the primary current, or, to be more strictly correct, 

 the primary m. m. f. 



O M is proportional to the terminal voltage of 1 10 volts in our case. 



SCALE FOR M. M. T. 

 01234 



5 AMP. 



SCALE FOR FIELDS 



20 40 60 80 



100 VOLTS 



Fig. 44- 



M D is proportional to ti n, the ohmic drop in the primary. It is 

 drawn perpendicular to Xi, as the field that would be equivalent to 

 the throttling action of the ohmic resistance must be in quadrature 

 with the voltage necessary to overcome it 



O D, then, is the primary flux F\. 



81 



