i i\ J..MI HT1UEMUHI It 



then to the client point In other wonk, di 



is always an increment m the tame direction an tl 



ftufe 1. To determine the position of loadinc to five 



a miixiiuiiin p.. **, place tin* live load on the |rt 



of tl,,- I .ridge correspondnm t., thr ji....itivo portioo of thr 



influence lin a wheel fir*t immedin rijtfii 



-lit point that has a fugaJuv coefficient and then 



<LS 



to the ! iiis point. Calculate the value of 



oLr 



for each of them succeiwive portions of loading 1- 



iri 

 the sign of ^ ehang-> fn.m - t<> -, a position of load- 



ing for maximu! treas is determined. 



Rule 2. To determine the IK.MM..I, of loading to give 



a numerically maximum in-native Stress, place t load 



on that part <>\ the \m rrenponding to the negative 



-I.- influence linr. Try a wheel fimt inunedi- 



atrly \<> the ri^ht of a salient |>oint that has a potto iv coef - 



i and then JIM to the !!'! of this jxiint. ('alrulatr 

 10 



thr value of j- = 1'^ II' for each of these BUCC(ISSi pom- 



d8 



tions of loading. If the sign of -. changes from - to -f-, 



a portion of loading for numerically maximum 

 stress is determined. 



It will l>e noted that the negative coefficients C 

 nt those salient points where the angles of the 

 line point upward, \\hile the jxiMtive icfficienUi C 

 at those salient p<>mN where the angles point 



It is umie. e^ar\ to seek a position of loading for 

 mitm /*., <-w liy placing a wheel successively to thr 



riilht and to the left Calient f^int which HAM a pott- 



ti^ 

 live coeflicie if g - 2CIF be -h when the wheel 



to the riuht of tin- )>oint. it would have a still larger + 



^ ><( C $ 



