HOW TO BALANCE A RATION 



143 



2 Ibs. X 0.918 1.836 Ibs. of dry matter. 



2 Ibs. X 0.372 = 0.744 Ibs. of digestible protein. 



2 Ibs. X 0.169 0.338 Ibs. of digestible carbohydrates. 



2 Ibs. X 0.122 -- 0.244 Ibs. of digestible fats. 



In the same way we arrive at the digestible amounts contained 

 in 6 Ibs. of shelled corn, 6 Ibs. of wheat bran and 10 Ibs. of 

 timothy hay. Then we add together the dry matter and digesti- 

 ble nutrients in the cotton-seed meal, shelled corn, wheat bran 

 and timothy hay and compare the result with the standard. 



To reduce the fat to terms of carbohydrates we must multiply 

 by 2.25. 0.804 X 2.25 = 1.809. 11.038 + 1.809 = 12.847 Ibs. 

 total digestible carbohydrates. 12.847 (total digestible carbo- 

 hydrates) -f- 2.218 (digestible protein) = 5.8. That is, the 

 nutritive ratio is i: 5.8. This trial ration is stated as follows: 



Balancing the Ration. This trial ration is not entirely satis- 

 factory. It is almost correct for dry matter and near enough 

 to the standard in protein. It is too low in carbohydrates. We 

 must correct the ration to make it more nearly approximate the 

 standard. Let us add 3 Ibs. of timothy hay and see what effect 

 it has on balancing the ration. 



