WEIGHT OF ORE IN A LODE. 



c A E = angle the lode B A E F makes with the horizon. 

 The angle A E c 90 c A E. 



E represents the point of the lode directly under c, /.&, 

 the point where the perpendicular line to A c cuts the lode 

 in depth. 



The cubical contents in feet of the lode = A B x A E x 

 thickness of lode. 



Now A E = 



A c 



r^. and A B and angle 

 v sm (90 E A c)*' 



E A c and the thickness of the lode, are also known. > 



As in the previous example, the weight in tons can be ob- 

 tained, supposing the average specific gravity of the ore is 

 known. 



FIG. 70. 



To find the value of the property, 



weight in tons x average yield in ounces per ton of ore, 

 X value of the metal per ounce, 

 = whole value. 



* Thus, if E A c is 60, A a = - - 6 



