74 



Heredity and Eugenics 



FEMALE 



MALE 



barring B, the male of pure race is plainly BB and every 

 sperm is B. But the female clearly contains only one B 

 and cannot be made to contain two. Perhaps a second B 

 is kept out by some structural element, X, the distinctive 

 structural element of the female individual. Then the 

 eggs will be of two sorts: B and X (Fig. 37). Since the 

 sperms are all 5, the first type of egg when fertilized will 



contain BB, a homozy- 

 gous barred individual 

 and a male, since it 

 lacks X; the second 

 type will contain BX, 

 a bird heterozygous in 

 barring, and a female, 

 since it contains X. 

 This agrees with the 

 experimental result. 



A heterozygous 

 barred male will form 

 two kinds of sperm, 

 only one of which will 

 contain B. If such a 

 male be mated with a barred female, four sorts of zygotes 

 should result as follows: 



Gametes of heterozygous barred male = B and 

 Gametes of barred female =B and X 



Zygotes =B B (homozygous barred male); B (heterozygous 

 barred male), B X (barred female), and X (non-barred female). 



The observed result of this cross accords fully with the 

 foregoing expectation. 



The sex-limited inheritance of barring in fowls may be 

 explained, as we have just seen, on the assumption that the 



FIG. 37. Diagram of sex-limited inheritance 

 when the female is a heterozygote, as in barred 

 fowls. X, female sex determiner; B, barring. 



