Art. 132. STRESSES IN A SUBDIVIDED WARREN TRUSS. 255 



04. A 



D\= J X 22,000 X = - 13,500 Ibs. D. L. 

 28 



CM A 



- |X40,OOOX-^= +36,900 Ibs. L. L. 



28 



+23,400 Ibs. Total reversal. 



34.4 



Z>', = li X22,000 X-- = +40,500 Ibs. D. L. 

 28 



= I X 40,000 X=- 18,500 Ibs. L. L. 



28 __ 



No reversal. 

 Ferficofc. 



7 i = F 3= _8_x22,000 - 16,000 Ibs. D. L. 

 = 1X40,000 -40,000 Ibs. L. L. 



-56,000 Ibs. Total. 

 = + 6,000 Ibs. D. L. Total. 



Chord Stresses. 



90 



? 2 = U 3 = 6X22,OOOX-=+ 94,300 Ibs. D. L. 



9O 



= 6X40,OOOX- = +171,400 Ibs. L. L. 



28 



+265,700 Ibs. Total. 

 U 4 = 8 X22,OOOX^= +125,700 Ibs. D. L. 



9O 



= 8 X40,OOOX = +228,600 Ibs. L. L. 



28 



+354,300 Ibs. Total. 



; 1= L 2 =3JX22,OOOX = - 55,000 Ibs. D. L. 



28 



90 



=3iX40,OOOX = -100,000 Ibs. L. L. 

 - 155,000 Ibs. Total. 



20 



= L 4 =7iX22,OOOX- = - 117,800 Ibs. D. L. 



28 



9O 



=7JX 40,000 X- = -214,300 Ibs. L. L. 



-332,100 Ibs. Total. 



133. Stresses in a Half-hip Truss. The end panels 

 of a half -hip truss (Fig. 187) are like those of a Warren truss 



