DESIGN OF RIVETED JOINTS. 

 Then the maximum stress on the outside rivet will be, 



M7 



Thr .ill.iwable value of r for a % in. rivet is 14,400 Ib. in double shear and 10,500 Ib. in 

 Inuring on }<j in. web plate (Table 1 14), so the joint is satisfactory. 



Net area of flange angles = 9.50 in.* 



One-eighth of area of web plate = 3.00 " 



Total flange area 12.50 " 



:B 



SiS. 

 rK~ 



00 



oo 



"T ? 



*!* *J 



,00000000 o o o o ! 



OOOOOO|OOOOOO| 



FIG. 16. DETAILS OF A WEB SPLICE. 



Riveted Joints in Cylinder, Pipe or Tank. A cylinder 46 in. in diameter is to be designed to 

 carry an internal pressure of 100 Ib. per sq. in* Compute the required thickness of plate and 

 design a longitudinal double riveted lap joint of equal efficiency for all parts. Reduce to com- 

 mercial dimensions and investigate. 



Solution. The unit stresses allowed by specifications for tanks are/t = 12,000 Ib. per sq. in., 

 ft = 12,000 Ib. per sq. in.,/ e = 24,000 Ib. per sq. in., for shop joints. 



From "Structural Mechanics," Chapter XVI. 



e = 2 / _ _ 2 X 24,000 



ft + 2/ e 12,000 + 2 X 24,000 



= 0.80 



w-D 



loo X 46 



2f t -e 2 X 12,000 X 0.80 

 d = 4 f -t = 4 X 24,000 



*/ 3.1416 X 12,000 



= 0.24 in. 



X .24 = 0.61 in. 



(I6a) 

 (166) 

 (I6c) 



This joint would have the efficiencies for tension, compression and shear all equal, but the 

 sizes could not be obtained from stock so that the joint must be altered to suit commercial sizes. 

 Make t = % in., d = % in., p = 3 in., and investigate. the joint. 



2 



p 



6,900 



(p - d)t ~ 2.375 X 0.25 

 P 6,900 



2t-d 2X0.25X0.625 



P 6,900 



. - ^ ^ T T ^rw\ 1 



1 1, 600 Ib. per sq. in. 

 = 22,100 Ib. per sq. in. 



(140) 

 (146) 



