Ivi Table* // Xtnti.ti<>inx and Blometric'uin* [ X X X 1 1 XXXIII 



Illustration (ii). Find F (87614). 



F (87614) 77(il4 x 67614 x 57614 x 4 7614 x 37614 x 27U14 



x 17614 r(17614). 



log T (87614) = -889.9401 + log T(17614) 

 830,0366 

 760,5280 

 677,7347 

 575,3495 

 441, 1 2! i:; 

 245.8580 



= 4-420,5762 + log T (17614). 

 log F (1761 4) = 1-964.5473 + '4 [1113] 



= 1-964,5918. 

 . . log T (87614) = 4-385,1680. 



Hence F (87614) = 24275-49. 



TABLE XXXII (pp. 6263) 



TABLE XXXIII, A and B (p. 64). 



Subtense from Arc and Chord in the case of the Common Catenary. (Julia Bell 

 and H. E. Soper: see Bwmetrika, Vol. vm. pp. 316, 338, and Vol. ix. pp. 4012.) 



If c be the parameter of the common catenary, then we know that 



y = c cosh u ................................. (xliii), 



where u = x/c is its equation. 

 If the chord be 2#, then 



subtense/chord = (y c)/(2x)\ 



_ (sinh $uY \ ..................... (xliv), 



"' } 



sinh M 

 arc/chord = .............................. (*lv), 



arc chord _ sinh u $ / i *\ 



"^hord ~iT 'loo' 



Mllitrlisi- (sinh JH)-' _ a , , ..v 



chord" ~iT = K)0 

 Corresponding values of a and ft are given in the Tables XXXII and XXX 1 1 1 





