28 TRANSMISSION LINE FORMULAS 



TABLE III. K FORMULAS FOR TRANSMISSION LINES. 

 CONDITIONS GIVEN AT RECEIVER END. 



Accurate within approximately ^ of i% of line voltage up to 100 miles, 

 and | of i% up to 200 miles, for lines with regulation up to 20%. 



A . = 6 (cycles)^ #= 2>l6 f or 6o cycles. K = 0.375 for 25 cycles. 

 10,000 



Conditions given: 



K.V.A. = K.V.A. at receiver end. 



E = Full load voltage at receiver end. 

 cos 6 = Power factor at receiver end. 

 K.W. = K.V.A. cos 6. 



r = Resistance of conductor per mile. (From Tables VII-VIII.) 

 x = Reactance of conductor per mile. (From Tables IX-XII.) 

 / = Length of transmission line in miles. 



Then P = I00 K -V- A - cosg = i n _ p h as e current at receiver end 



hi 



(in total amps.) . 

 Q = looo K.V.A. sin = Reactiye current at rece iver end 



(in total amps.), when current is 

 lagging. 

 _ _ looo K.V.A. sin 9 ^ ^^ ... 



