' K FORMULAS 35 



Current in total amperes* 



(7) Vjlf 2 + # 2 at receiver end. (8) Vjkf 2 + N<? at supply end. 

 K.V.A. 



( g ) _L_ t p + -% ) VM 2 + 2V 2 at receiver end. 

 1000 \ 2 r I 



(IQ) E 8 VMo 2 + N Z at supply end. 

 K.W. 

 (i i) - (FM + GN) at receiver end. (i 2) ^^ E 8 M at supply end. 



Power factor, in decimals. 



(13) , + CT at receiver end. 



(14) . _ _ at supply end. 



In-phase current in total amperes* 



- "*" at receiver end. (16) M at supply end. 



Reactive current in total amperes* 



(17) - TT- at receiver end. (18) No at supply end. 



When this quantity is positive, the current is lagging. 

 When this quantity is negative, the current is leading 

 K.W. loss in line. 

 (19) - -(E S P 8 -FM-GN). (20) -^Esb 



Per cent efficiency of line. 



. x ioo(FM + GN) 



(21) - -^ per cent. 



-C-S/3 



Total amps. 

 * Amperes per wire, three phase, = 7= 



V 3 



Total amps. 

 Amperes per wire, two phase, = ti. 



