38 TRANSMISSION LINE FORMULAS 



Pi = 71.15 + 13.29 = 84.44 amps. 

 Qi = 25.46 + 13.56 = 11.90 amps. 

 Then by the K formulas, 



Ai = 105,360 5120 + 4180 1410 



= 103,010 volts. 

 B! = 2200 + 9940+ 590 



= 12,730 volts. 



T> 2 



AI -\ = 103,800 volts 



2A l 



= voltage at the supply end of the line. 



[By the fundamental formulas, supply voltage = 103,900 volts 

 (Prob. B, Chap. VI).] 



PROBLEMS, CHAP. V. 



(K FORMULAS.) 



1. Find, by means of the K formulas, the voltage drop from 

 the supply end to the receiver end (the line drop) of the following 

 line: 



Length of line 200 miles. 



Spacing 9 feet. 



Conductor No. ooo aluminum cable. 



Load (at receiver end), 4500 K.V.A., 66,000 volts, 80% P.P., 

 three phase, 60 cycles. 



Ans. 6650 volts. 

 [By the fundamental formulas, 6700 volts. (Chap. VI, Prob. A).] 



2. Find the regulation of the line in Prob. A, Chap. V. [See 

 Prob. A, Chap. III.] 



Ans. 9-37%. 



[By the fundamental formulas 9.40%. (Chap. VI, Prob. 2.) 

 Error 0.03% of line voltage.] 



3. Find the per cent regulation and voltage drop of the following 

 line: 



Length of line 75 miles. 



Spacing, 8 feet, regular flat spacing. 



Conductor No. oo aluminum cable. 



Load (at receiver end), 10,000 K.V.A., 88,000 volts, 85% P.P., 

 three phase, 25 cycles. (Prob. 7, Chap. III.) 



, 7-35% reg'n, 7.13% drop. 



