82 TRANSMISSION LINE FORMULAS 



and C. Then the reactive voltage between these conductors 

 for the next mile is 



(1.50 - 0.8667) (so.s + 741-1 log-} Ij 2 TT/ X io- 6 



+ (0.50 + 0.8667) 74I-I (log- - log-) Ij 2 TT/ X 



\ p P/ 



io 



Let the Hne be transposed again. Then for the third 

 mile the reactance voltage between these same two con- 

 ductors is 



(1.50 - 0.8667) ^80.5 + 741.1 log -) Ij 2 7T/ X io- 6 



+ (0.50 + 0.8667) 741.1 (log- - log-) Ij 2 TT/ X io- 6 . 



\ p P/ 



The total reactive voltage for the three miles is 



(1.50-0.8667) j 80.5X3 + 741.1 (log- + log- + log-) \ 

 ( V p p p/ ) 



X Ij 2 7T/ X IO- 6 . 



/Thus the average reactive voltage per mile, which is the 

 same for all phases, is, in absolute value, 



1.732(80.5 + 741.1 log- -) / 2 TT/ X io- 6 . 

 V P / 



Now 1.732 / = the total amperes. 



K.V.A. 



E 

 Therefore the drop in line voltage, in absolute value, is 



80.5 + 741.1 log - 2 TT/ X io- 6 



in volts per total ampere per mile of transmission line, 

 where 



