102 TRANSMISSION LINE FORMULAS 



the second half of the expressions for voltage and current 

 is negative, since power is now flowing away from the point 

 where the voltage is specified, instead of toward it. Thus 

 we have the series for F +jG and M + JN. 



At no load, the conditions are really not all specified at 

 the supply end, but the current is specified to be zero at 

 the receiver end, and this necessitates the use of special 

 series. From Table V we have the ratio of the voltage at 

 the two ends of the line, 



E 0a _ AQ + jBp 



E ~~ E 



YZ , F 2 Z 2 



-1 1 h etc 



2 2.3.4 



This ratio is independent of the voltage E, and depends 

 only on the constants of the line. Thus, if s , the voltage 

 at the supply end at no load, is given, we can obtain the 

 no-load voltage at the receiver end from the equation, 

 | / +Z Z J^ZL N 



EQ \ 2 2-3.4 / 



CFZ F 2 Z 2 \ - 1 



iH h j --fete.) , 

 2 2-3-4 / 



which, when expanded by the binomial theorem, gives 



EQ = F +JG 



= E 8 (i - -FZ + ^F 2 Z 2 - F 3 Z 3 + -^F 4 Z 4 - etc.) 



\ 2 24 720 8064 / 



(16) 



as in Table VI. 

 The no-load current at the supply end is 



CV7 v 2 7 2 \ 



i+ J + -+ etc.), 



2-3 2.3.4-5 



as in the equation for C +JD . 



