TABLE VI. VALUE OF LAND, CROP, OR WORK, AT PER ACRE. 189 



3. Required the value of 15 acres, 27 poles, of growing irheat, 

 at 9 17s. 6d. per acre ? 



This may be found by two methods, either by finding the value 

 for 9 1 7s., and then for 6d. ; or by finding the value for 9, and 

 then for 17s. 6d.; as follow: 



For 15 acres at 9 17s. add the value 



for 5 and 10 acres, = . . 147 15 



" 27 poles at 9 17s. = . 1 13 2f 



" 15 acres at Gd. add the value for 



5 and 10 acres, = . 076 



" 27 poles at Gd. = . . . 001 



Value of the 15 acres, 27 poles, 149 15 9| 



For 15 acres at 9, add the value for 5 and 



10 acres, = . . 135 



" 27 poles at 9, = . . 110 4| 



" 15 acres at 17s. Gd. add the value for 



5 and 10 acres, = . 13 2 6 



" 27 poles at 1 7s. Gd. = . . 2 11J 



Value of the 15 acres, 27 poles, as above, 149 15 9| 



4. A potatoe field measures 5 acres, 3 roods, 12 poles ; what is 

 its value at 35 1 Os. per acre ? 



As 35 10s. is not to be found in the Table, either halve the 

 rate, or divide it into two parts, say of 20, and 15 10s. ; find 

 the value of each separately, and add their sums together, for the 

 value of the field. Both these methods may be shown. 

 And first by halving 35 10s. = 17 15s. 



5 acres at 17 15s. per acre, = . 88 15 



3 roods at ditto, = . . 13 6 3 



12 poles at ditto, = . 1 6 7J 



103 7 10J 

 Which multiply by . 2 



Value of the field at 35 10s, per acre, 206 15 9 



By dividing 35 10s. into parts of 20 and 15 10s. 



5 acres at 20 per acre, = . . 100 



3 roods at ditto, = . 15 



12 poles at ditto, = . . . 1 10 



5 acres at 15 10s. per acre, = . 77 10 



3 roods at ditto, == . . . 11 12 6 



12 poles at ditto, => . . 133 



Value of the field, as above, 206 15 9 



