428 TABLE XXVI. - CUBIC CONTENT OP OBLONG STACKS. 



The exact content of the portion above the eaves is found br 

 taking the length and breadth at the eaves by half the perpen- 

 dicular height from the eaves to the top of the stack, and finding 

 the content by the Tables, which is to be added to the content of 

 the body of the stack, which must be taken by itself. Such 

 minuteness, however, is seldom attended to. 



EXAMPLE* Required the content of a hay stack, the mean 

 breadth being 15 feet, the length 50 feet, the perpendicular 

 height from the bottom to the eaves 13 feet, and from the eaves 

 to the top of the ridge 7 feet. 



The mean height is 13 feet added to the half of 7 feet = 16J ; 

 feet, and as this height is not in the Table, we take first the ; 

 height 15 feet, and then 1 J foot. 



ind the breadth 15 feet on the top of the page, 



and opposite the length 50 feet, under the Yds. Ft. 

 height 15 feet, stands ..... 416 18 



And opposite the same length, under the height 



1J foot, stands . . . . . * 41 18 



the solid content, * 458 9 



And, suppose we wisti to know the number of Imperial stones 

 in the stack, at the rate of 14 stones per cubic yard, turn to 

 Table XXVIL, 



Where, under 14 stones, opposite 450 yards, Stones. 

 stands ........ 6300 



And, opposite 8 yards, stands . . . . 112 



The number of stones in the stack, . . 6412 



To calculate the above by the pen, multiply the mean length 

 and breadth together, and their product, multiplied by the mean 

 height, gives the solid content, in the same name as the dimen- 

 sions were taken in; if in inches, divide by 1728 to reduce to 

 feet ; and, if in feet, divide by 27 to reduce to solid yards. 



Taking the foregoing example, 



15 X 50 = 750 X 16| = 12375 cubic feet, 

 12375 -5- 27 458 yards, 9 feet ; 

 and 458 X 14 = 6412 stones. 



