TABLE XXVIII. 



SHOWS THE CONTENT OP TANKS, ETC., OP A CYLINDRICAL FORM, IS 

 CUBIC YARDS AND FEET, FROM 4 TO 15 J FEET IN DIAMETER, AND 

 FROM 4 TO 14: FEET IN DEPTH. 



THE depths are found in the left-hand column of the pages, 

 and the diameters along the tops of the other columns, in their 

 order; and the content, at any given diameter and depth, is 

 found opposite the given depth under the given diameter. 



In calculating the Table, fractions of a half-foot and under aro 

 neglected, when above a half- foot, they are reckoned 1. 



EXAMPLE. What is the cubic content of a cylindrical tank, the 

 diameter of which is 12 J feet, and the depth 8 feet? 



Look in the Table for the diameter 12^ feet, and under which, 

 opposite the depth 8 feet, is found 36 yards 10 feet, the cubic 

 content. 



To calculate the content of a cylindrical tank, having the 

 diameter and depth given, 



RULE 1. Square the diameter, multiply the product by the 

 depth, and by .7854, and, if the dimensions are given in feet, the 

 result is the content in cubic feet ; if the dimensions are given in 

 inches, in place of .7854, multiply by .00045452, which will also 

 give the content in cubic feet, which divide by 27, to reduce to 

 cubic yards if required. 



2. Or, square the diameter, multiply the product by the depth, 

 and by .02909, the product is the content in cubic yards, if the 

 dimensions are given in feet; if the dimensions are given in 

 inches, in place of .02909, multiply by .000016834, and the pro- 

 duct is also the content in cubic yards. 



Take, for exercise, the above example, by the rules in their 

 order. 



By Rule 1, the dimensions in feet, 



12.5 2 = 156.25 X 8 = 1250 X .7854 = 931.75 cubic feet. 

 Dimensions in inches, diameter 150 inches, depth 96 inches, 



150 2 =22500X96=2160000X.000045452=981.7632 cubic feet, 

 and 981.7632, divided by 27, gives 36 yards 9.7632 feet, or 

 nearly 9| feet. 



