5G2 TABLE XXIV. SOLID CONTENT OP CYLINDRICAL TREES, ETC. 



The girth being given in inches, and the length in feet, will 

 fall under Case 2, and, after having conducted the calculation 

 according to the present Rule, the last product must be multiplied 

 by .000552022, or divided by 1809.56, as directed under that 

 Case. 



128 2 = 16384 By using the divisor 1809.56. 



128 X^ = 12288 !809.56) 18944000(104.638432 



Jd of 15 ft. the length = 



37888 



189440 

 Multiply by .000552622 



378880 

 378880 

 1136640 

 378880 

 947200 

 947200 



Content, 104.688711680 

 Subtract con- 

 tent found as 

 a cylinder, . 103,981355520 



Deficiency = 

 T Jyth part = 



180956 



848400 

 723824 



1245760 

 1085736 



1600240 

 1447648 



782720 

 723824 



.707356160 

 12 



8.488273920 

 4 



99008 



It may be observed that two 

 cyphers are annexed to the 

 or nearly SJ in. 1.953095680 dividend, to compensate for 



the two places of decimals in 

 the divisor ; and also that it is 

 unnecessary to carry the quo- 

 tient further than three places 

 of decimals. 



It was stated in the introduction to the preceding Table, that 

 by the usual rule for measuring round timber, the content shown 

 was less than the truth in the proportion of 11 to 14, or, less in 

 that proportion than the content found by the present Table. 

 There is, however, a source of additional loss> in the fact that the 

 tree is measured as a cylinder, in place of being measured as the 

 frustum of a cone. The amount of error from this cause varies 

 in the proportion of the difference of the girths, or diameters of 



