58 PHYSIOLOGICAL, CHEMISTRY 



CH 2 OH CH 2 OH 



CH OH (CH OH) 3 



CH OH -> CH OH 



CH OH CH =N NH C 6 H 5 +H 2 



CH OH 



CHO +H 2 N NH C 6 H 5 



The product is a hydrazone. A second molecule of phenylhy- 

 drazine then removes two H atoms from the group next the end 

 carbon atom, and is converted into aniline and ammonia. 



CH 2 OH CH 2 OH +H 2 NC 6 H 5 +NH 3 



I I 



(CH OH) 8 - (CHOH) 3 



I I 



CHOH +H 2 N NH C 6 H 5 C=0 



I I 



CH=N NH C 6 H 5 CH=N NH C 6 H 5 



A third molecule of phenyl hydrazine now reacts, forming 

 the osazone. 



CH 2 OH CH 2 OH 



(CHOH) 3 + H 2 N NH C 6 H 5 (CHOH) 8 + H 2 



C=0 C=N NH C 6 H 5 



CH==N NHC 6 H 5 C =N NH C G H 5 



H 



In place of phenyl hydrazine, its hydrochloride often is used, 

 as this compound is more soluble and more stable than the 

 free base. 



The Molisch Test. If to a solution containing a carbohy- 

 drate a few drops of 15% alcoholic oc naphthol are added, and 



