CURRENT-LIMITING REACTORS 



483 



For a ground on one line at the point A, giving a single-phase 

 short-circuit, currents flow, as shown by the arrows. An equiva- 



G, r-= 



FIG. 300. Calculation of Single-phase Short-circuit Currents. 



Z 



-7* 



-12* 



25' 



-10* 



v* 



-10* 



FIG. 301. Equivalent Short-circuit Corresponding to Fig. 300. 



lent circuit for Fig. 300 may be drawn as shown in Fig. 301. 

 This circuit may be solved as follows: 



10+3.33+4+4 = 21.33 

 12+4+10+10 = 36 

 1 1 1 



11 .0469 +.0278 .0747 

 21.33 + 36 



3+2+3+7 = 15 

 13.4+15 = 28.4 

 100 



13.4 



28.4 

 .0469, 



X/ = 3.52X57.7 = 203 

 Q747 X 203 = .628 X 203 = 127.5 amps. 

 *2 = ^^ X 203 = .372 X 203 = 75.5 amps. 



