MANURING. 



TO FIND THE NUMBEE OF CAET LOADS, THE NUMBEB OF 

 HEAPS IN EACH LOAD BEING KNOW, WHICH WILL BE 

 EEQUffiED FOE MANUEING ANY QUANTITY OF LAND, 

 THE EOWS AND HEAPS BEING EQUALLY DISTANT, 



RULE. Reduce the quantity of land to be manured and 

 the distance of the heaps or rows to the same denomination ; 

 the quantity of land, divided by the product of the square 

 of the distance of the heaps or rows, multiplied by the 

 number of heaps in the load, will give the number of loads 

 required. 



Ex. Required how many cart loads, of 6 heaps each, 

 will be required for 12^ Imperial acres, the distance 

 between the rows and heaps being 6^ yards ? 



121 acres = 60500 yards, or 12 acres = 78408000 inches. 

 Dist. of heaps 6| yards. 6| yards = 234 inches. 



6i 234 



234 



Sq. of dist. 42| 



Heaps in load 6 54756 



6 



60500 



2 328536)78408000(238f f loads. 



507 )121000(238|f loads. 



To find the number of Cart Loads from the Table: Look 

 for the distance of the heaps, left hand column, and for the 

 number of heaps in the load, upper line (large figures), then 

 directly under that number, and opposite to the distance of 

 the heaps, is the number of loads which would be required 

 for one acre ; then to find the number of loads for any num- 

 ber of acres, &c. multiply the number found in the Table 

 by the number of acres, &c. ; and when the quantity is less 

 than one acre, divide the number found in the Table by 

 whatever part the quantity is of one acre. Thus, to find 

 from the Table the number of loads for one acre, correspond- 

 ing to the distance, &c. of the above example, look opposite 

 6^ andunder 6, and there are found 19.09 loads, which, multi- 

 plied by 12 J, gives 238.62 loads ; nearly the same as before. 



