19 



The water, on the other hand, had its temperature raised 

 2.41 C. The amount of heat required to raise the tem- 

 perature of i gm. of water, through i C., is I calorie. 

 Hence i gm. of water in having its' temperature raised 

 through 2.41 C, must have absorbed 2.41 calories, and 

 60 gm. must have absorbed 2.41 x 60, or 144.6 calories. 



Since the heat lost by the zinc equals the heat gained 

 by the water, I55I 8 xS= l ^ 6 calorieS) 



=.093. 



The specific heat of zinc is .093, less than one tenth the 

 specific heat of water. 



EXPERIMENT 8. DETERMINATION OF THE SPECIFIC HEAT 



OF LEAD 



Pour into a glass beaker 200 gm. of water whose tem- 

 perature is somewhat below the temperature of the room, 

 and surround the beaker with cotton. Weigh out 100 gm. 

 of lead shot; put it into a metal cup and set the cup 

 in a vessel of boiling water. Allow the shot to heat for 

 10 or 12 minutes, stirring gently from time to time with 

 a glass rod. Note and record the temperature of the 

 water in the beaker and quickly pour the hot shot into 

 it. Stir gently for 2 or 3 minutes with the thermometer 

 and then note and record the temperature of the mixture. 



Tabulate the results and calculate the number of calories 

 of heat lost by the lead, remembering that the heat lost 

 by the lead equals the heat gained by the water. Then 

 calculate how many calories each gram of lead must have 

 lost, and, finally, how many calories each gram would have 

 lost if its temperature had been lowered only i C. This 

 is the specific heat of the lead. 



