02 ANSWERS TO PRACTICAL QUESTIONS 



44. Find how much sulphuret of calcium is madt 



45. Find how much sulphur could be saved (if none were 

 lost) from the CaS. 



The following reactions show the chemical changes which 

 take place in the various stages : 



(1) NaCl + S0 3 HO = NaO.SO, +HC1. 

 NaO.SO, + 2C = NaS + 2CO a . 

 NaS + CaO.C0 2 = CaS+NaO.CO,. 



From the (i) reaction we find how much Glauber salt will 

 be made from 500 Ibs. of common salt. To do this we first 

 find how much Na there is in 500 Ibs. NaCl; and, secondly, 

 how much NaO.SO 3 that amount of Na will make. 



Na : NaCl : : x : 500 Ibs. 

 23 : 58.5 : : x : 500 Ibs. 

 x = 196 frV Ibs. (Na). 

 Na : NaO.SO, : : 196 -ft\ Ibs. : . 

 23 : 71 :: 196-^ : x. 

 Ibs. (NaO.SO,). Ans. to tostpnto. 



Na : NaO.CO 3 : : 196 -ftV Ibs. (Na) : *. 



23 : 53 : 196 -fo Ibs. : x. 

 Ibs. (NaO.C0 3 , " Soda"). Ans. to 40th pnk 



Cl : NaCl : : x : 500 Ibs. 

 85.5 : 58.5 : : x : 500 Ibs. 



a- = 303 -f^y Ibs. (Cl). 

 Cl : HC1 :: 303 -^Ibs. : x. 

 85.5 : 36.5 :: 303^ Ibs. : *. 



AM. to 4Sd pnb. 



Na : NaS :: 196 -j 6 ^ Ibs. (Na) : *. 



23 : 39 :: 196-^rVlbB. : x. 

 s 333 Va Ibs. (NaS). Ans. to 4M proo. 



888 / . (NaS) 196 -ffr Ibs. (Na) = 136 /ft- Ibs. (S). Ant. to Iro6. 15. 



S : CaS : : 136 -^f n. ( s ) * 

 x = 307 Vw Ibs. (CaS). Ans. to 4Mk prob 



