47 



BEDS. 



From the centre, D, at the distance, DA, 

 describe the semicircle AHB, and from the 

 same centre at the distance DC describe 

 the semicircle CKE. Bisect the lines 

 AC, EB, in the points F and G, and 

 from these points as centres, with the 

 radii FA and GB, describe the semi- 

 circles ALC, BME, which complete the 

 end of the bed. A bed of horseshoe 



dividing AB into two equal parts in M, 

 and from M as centre, with the distance 

 MA on MB, describing the dotted circle 



FIG. 3. SEMICIRCULAR RIBBON OR 

 HORSESHOE BED. 



form may be produced by extending the 

 circumferences of the circles AHB, CKE, 

 and forming the extremities of the bed, 

 by drawing straight lines as DN, DO, 

 intersecting the circumference of the 

 circles. From Fig. 3, it may be easily 

 seen how to form a bed of an 5> or ser ' 

 pentine form, by repeating the process 

 already described on the line AB produced 

 towards A or B, or continuing it on the 

 lines DN or DO produced towards N or O. 



4. Serpentine Bed. A bed in a serpen- 

 tine form is shown in Fig. 4 which is very 

 easily laid out. Firstly, a straight line, 

 equal to the length of the bed from end to 

 end, as AB, is marked out, and this is 

 divided into three equal parts in the points 

 c and D. The divisions AC, DB, are again 

 subdivided into two equal parts in the 

 points E and F. From E and F, as centres, 

 with radii EA, FB, the semicircles AGC, 

 BHD are described, and from c and D as 

 centres, with radii CA and DB, the semi- 

 circles AKD, BLC, are described, com- 

 pleting the outline of the bed. By 



FIG. 4. SERPENTINE BED. 



AN BO, a bed of a curved pear-shaped form 

 is obtained, as AGCLBO. The fault of the 

 serpentine bed shown by the solid lines in 

 Fig. 4 is that it is too sharp at the ex- 

 tremities. Another serpentine form that 

 has not got this fault is shown in Fig. 5. 

 In this the straight line AB is divided, as 

 in the above, into three equal parts, and 



FIG. 5. ANOTHER FORM OF SERPENTINE BED. 



each of these parts is again subdivided in 

 E, G, and F. Perpendiculars on opposite 

 sides of AB are erected to AB at E and F, 

 as EH and FK. In EH, take EL, equal to 

 EA or EC, and in FK take FM, equal to FB 

 or FD. Join LM, and from L through c 



