CASK-GAUGING. T9 



the bung to the head (not from head to head) is so small, 

 that they are, with scarcely an appreciable difference in the 

 results, usually regarded as the two equal frustums of a 

 cone, and are very accurately gauged by three dimensions, 

 as follows : 



To find the contents of a cask ~by three dimensions. 



RULE. Add the bung and head diameters in inches, and 

 divide them by 2 for the mean diameter ; find the area of 

 the mean diameter in the table of the areas of circles on 

 page and multiply it by the length of the cask in 



inches ; then divide the product by 231 (the cubic inches 

 in a gallon), and the quotient will be the number of gal- 

 lons the cask contains. 



EXAMPLE. What are the contents in gallons of a cask, 

 the bung diameter of which is 22 inches, the head diameter 

 20 inches, and the length 32 inches ? 



SOLUTION. 22 + 20=42 2=21, mean diameter: then 

 346.36, area of mean diameter, x 32=11083.52-^-231 = 

 47.98 gallons. Ans. 



When the cask is much bilged or rounded from the bung 

 to the head, a more accurate way is to gauge by four 

 dimensions, as follows : 



To find the contents of a cask by four dimensions. 



RULE. Add the head and bung diameters in inches, and 

 the diameter taken in inches in the middle between the 

 bung and head, and divide their sum by 3 for the mean 

 diameter ; find the area of the mean diameter in the table 



