80 CASK-GAUGING. 



of the areas of circles on page and multiply it by the 

 length of the cask in inches and divide the product by 231 

 (the cubic inches in a gallon), and the quotient will be the 

 contents of the cask in gallons. 



EXAMPLE. What are the contents in gallons of a cask, 

 the bung diameter of which is 24 inches, the middle dia- 

 meter 20 inches, the head diameter 16 inches, and its length 

 40 inches ? 



SOLUTION. 24 + 20 + 16 = 603 = 20, mean diameter: 

 the'n 314.16, area of mean diameter, x40 inches, length = 

 12566.40-r- 231 = 54.4 galls. Am. 



