CAPACITY OF WAGON-BEDS. 83 



the product by 2150.42 (the number of cubic inches in a 

 bushel), and the quotient will be the capacity in bushels. 



EXAMPLE. What is the capacity of a wagon-bed 10 feet 

 long, 4 feet wide, and 15 inches deep I 



SOLUTION. 120 inches, length, x 48 inches, width, x 15 

 inches, depth, = 86400-^2150.42=40 bushels. Ans. 



RULE 2. Should the head and tail boards, or either of 

 them, be set in bevelling, add the top and bottom Jengths 

 together and divide by 2 for the mean length, and proceed 

 by the foregoing rule. Should the sides be sloping, add 

 the top and bottom widths, and divide by 2 for the mean 

 width, and proceed by the foregoing rule. 



Should the contents be required in cubic feet, divide the 

 product by 1T28 (the number of cubic inches in a cubic 

 foot), instead of 2154.42, and the quotient will be the con- 

 tents in cubic feet. 



