100 HYDRAULICS. 



.942 cubic feet discharged pei second. .942 x 3600 seconds 

 (one hour) =3391 cubic ft. discharged per hour. Ans. 



To find the pressure of a fluid on the bottom of a vessel, 

 cistern, or reservoir 



RULE. Multiply the area of the base in square feet by 

 the height of the fluid in feet, and their product by the 

 weight of a cubic foot of the fluid. 



EXAMPLE. What is the pressure on the bottom of a 

 cistern 10 feet in diameter and 8 feet deep, filled with 

 water ? 



SOLUTION. 78.54, area of bottom, x 8=628.32 x 62 Ibs., 

 the weight of a cubic foot of water, =39. 370 Ibs. Ans. 



To find the pressure on the side of a vessel. 



RULE. Multiply the area of the side in feet by half its 

 depth in feet, and that by the Ibs. per cubic foot of the 

 fluid. 



EXAMPLE. What is the pressure upon the sloping side 

 of a pond 10 feet square by 8 feet deep ? 



SOLUTION. 10 2 =100x4, half the depth, =400x62 Ibs., 

 the weight of a cubic foot of water, =25000 Ibs. Ans. 



NOTE. It is proper to remark that all of these rules, 

 while they are theoretically correct, do not pretend to em- 

 brace a variety of circumstances which affect the flow of 

 water through apertures, and which should be taken into 

 consideration in all cases. These circumstances cannot be 



