MISCELLANEOUS PROBLEMS. 523 



PROBLEMS. 



What is the cost of a 256 pound hog @ $7.50 per hundred? 



Solution. The unit of weight in fixing prices on the stock market 

 is "the hundred." Thus when we say cattle are 8.50 or hogs are 6.95, 

 ve mean that cattle are selling @ $8.50 per hundred pounds live weight, 

 and hogs are selling @ $6.95 per hundred live weight. 



As the number 256 is composed of 2 hundreds, and 56 units 

 which is 56/100 of a hundred, therefore to find the cost in the 

 above problem we can write the weight 2.56 hundreds. 2.56 x 

 7.50 = cost. 



1. Find the cost of 3,543 pounds of live weight in hogs @ 9.25. 



2. Find the cost of three prime steers, weighing 3,750 pounds 

 @ 8.75. 



3. What is the cost of 1,196 pounds of flour @ 2.50 per hundred? 



In rinding the cost of articles sold by the thousand such as 

 tile and lumber, place the period between the thousands and hun- 

 dreds, and multiply by the price per thousand. 



1. What is the cost of 7,645 tile @ 13.50 per thousand? 



The cost will be the product of the cost per thousand multi- 

 plied by the number of thousands, thus 7.645 x $13.50 $103.20. 



2. Find the cost of 1,675 feet of lumber <K 23.25 per thousand. 



3. What will be the cost of 234,865 brick @ 12.75 per thousand? 



Hay, sugar beets, coal, steel and a few similar articles are 

 quoted by the ton. When a problem involves a weight of less 

 than one ton, we can calculate the per thousand or hundred as 

 the case may be. Thus 1,760 pounds of hay @ $12.50 per ton 

 would be easily solved by stating the price @ $6.25 per thousand. 

 Then we would have 1.760 x $6.25 = $11.00. 



The Market Quotations. 



Short methods of calculation : 



1. Find the cost of 125,750 pounds of sugar beets @ 5.60 per ton. 



2. What is the cost of 1,275 pounds of coal @ $4.65 per ton? 



3. Find the cost of 2,365 pounds of hay @ $15.40 per ton. 



