MISCELLANEOUS WOEK 199 



„, . , . „^ 500 X 200 = 50,000 square yards. 



Tnangle ABD = ^ 



,. BCD ^ ^^^200 ^ ^^^^ ^^ 



„ AIP =^-^^ = 1,500 



Trapezoid IHPO = ^^— ^ x 60 = 3,300 „ 



U60N = ^iL±l? X 60 = 3,900 



GFNM='^-^-^ x%0 = 3,900 



„ FEML = 60^:50 ^ g^^ _ 3 3()Q 



Triangle ^LZ> = ?^^^ = 1,750 



117,650 



117,650 square yards divided by 4,840, the number of 

 square yards in one acre, gives 24* 308 acres as the area 

 of the ground. 



The area of the irregular figure containing the foui 

 trapezoids may be found by taking the mean length of 

 the two extreme offsets PI and LE — viz., 50. Add to 

 this the sum of the other offsets — viz., 190 — making 240; 

 multiply this figure by the extreme length of the figure 

 — viz., 240 — and divide by the number of spaces between 

 the offsets— viz., 4=14,400. 



To measure the same ground from the outside, it is 

 necessary to erect a square or parallelogram of known 

 dimensions upon one of the sides. 



Taking the line BC as the base, it is measured and found 

 to be 445 yards. From B and C perpendiculars are set 



