CORRELATED VARIABILITY. 



53 



Log (450X203 -27 5X185) =4.607 1869 



Log HK = - log 2 rr - .091489 log e 



= 9.2018201 -M8.9613689 + 9.63778428] 

 = 9.2018201-0.0397332 = 9.1620869 



= 4.6071869-(9.1620869 + 2 log 1113) =9.3521096 



.224962 =r 



Solving .034575r 2 +r-. 224962 = 0, 



1 X/f+4T034575 X .224962) 

 -2(7634575) 



2_ ! = _ .848608 



Coeff. r4 = 



A: 2 - 1 = - .968415 CoeflF. 



+ -069150 X 2.848608 X 2.968415 



.136967 



.024363r 4 + . 136967r 3 + .03457 5r 2 + r - .224962 = 0. 

 Applying Newton's approximation, we reach the result 



r = .2217. 

 (7 5095 + 303530&> 2 + 281 300^ t 



Log w =log*ff-*log(l-r 2 ) 



-Iog(l-r2)-log2] 



ht + k*-2rhk = 0.152315, l-r 2 = 0.950850. 



Logw =9.20182-9.989056-M9.637784 + 9.18274-9.978112-0.30103] 

 = 9.1779797 



Log 



9.828975-4.569743-9.177980 = 4.081253. 



/?!= 0.358614 

 Table IV: 



.358 .13983 

 22.2 

 .4 



fa = .14006 



Log E . r = 4 . 08 1 2530 + \ log 7 4426 . 858 

 E. r = 0.03289 



#2=0.093794 



.093 



.03705 

 27.3 

 3.5 



4> 2 = .03736 





