NITRIC ETHER. 419 



6. The heat of formation from the elements has been found 

 (p. 279)- 



C 2 (diamond) + H 5 + N + 3 = C 2 H 4 (N0 3 H) (liquid) +49'3 Cal. 



In the gaseous state it should be nearly + 42 Cal. 



The heat of total combustion of the liquid body by an excess 

 of oxygen, + 311'2 Cal. 



7. The following decomposition, 



C 2 H 4 (N0 3 H) = 2CO + H 2 + 3H + N, 



would liberate, the ether and water being liquid, + 71'3 Cal. at 

 constant pressure, -f 73 '5 Cal. at constant volume. All the 

 bodies being supposed gaseous, the heat liberated must have 

 nearly the same value. 



Lastly, the ether being liquid and the water gaseous, we 

 should have, -f 61'3 Cal. at constant pressure, -f 64'6 Cal. at 

 constant volume. 



For 1 kgin. we should have at constant pressure, the ether 

 and the water being liquid, 783'5 Cal. ; at constant volume, 

 791-6 Cal. 



We shall not here examine the other possible modes of 

 decomposition. 



8. The volume of the permanent gases, at the temperature t, 

 will be, for 1 equiv. = 91 grms. 



89 -3 litres (l + 7^)> the water being gaseous, 111 '6 litres 



\ 2ii o/ 



(l + 7^3) ; r> for 1 kgm, 981-3 litres (l + j~^ for the per- 

 manent gases, 1226 litres (l + f J if gaseous water be added. 



9. The theoretical temperature, at constant volume 



64000 



- = 2424. 

 26-4 



10. The permanent pressure, at (the liquid water occupying 

 198 c.c.) 



981 atm. 1016 kgm. 



n = 0198 r n - 0198* 



But this formula is only applicable to low densities of charge, 

 owing to the liquefaction of carbonic acid produced at high 

 densities. 



11. The pressure developed at the theoretical temperature and 

 calculated according to the laws of gases 



12137 atm. nr 12541 kgm. 

 n n 



2 E 2 



W 



