386 APPENDIX CALCULATION OF THE 



log-. cos. 93 27'3G"zzl. cos. 86 32' 30" 8-7804792 

 log. cos. 59 24' 30" = 9-7066463 



18-4871255 



log. sin. 105 5'=1. sin.74 55'zz9- 9847740 

 log. sin. 47 47' .... =9-8695891 



19.8543631 



To extract the square root of this quotient, 1.3672376 



divide it by 2, and f is 0-6836188 

 log. R 10- 



log. sin. |V e f d = 9-3163812 



therefore \ y efd = 11 57' 28", and consequently 

 V efd = 23 54' 56". 



log. cos. 93 27' 30"r=l. cos. 86 32' 30" = 8.7804792 

 log. cos. 45 40' 30" = 9-8443079 



18-6247871 



log. sin. 105 5 / =].sin.74 55'z=:9-9847740 

 log. sin. 34 3' .... =9-7481230 



- 19-7328970 



divide by 2 . . MOS1099 



and J is ... 0-5540549 

 log. R ; =10- 



log. sin. | V d fS = 9-4459451 



Therefore J V d fg = 16 12/ 49/ ', and consequently 



V dfg 32 25' 38". 



Now as we know the angle e df fdg = 101 55' 

 we therefore know the angle d ef 45 10' 4" 



and dgf i=45 39' 22" 



and hence dfide :: sin. 54 10' 4" : sin. 23 54' 56" 

 :: 8107 : 4054 



:: 4 : 2 



