NOEMAL PEOCESSES OF ENEEGY METABOLISM 565 



The heat production then would be : 



90.56 X 3.29":= 297.9 Cal. 

 467.12 X 3.56 = 1662.9 " 

 157.0 X 3.19 = 481.7 " 



Total 



2442.5 



Kauffmann confirmed the correctness of this method of calculation by 

 means, of a calorimeter (p. 571) suitable for dogs. His results may be 

 summarized thus : 



TABLE 6 



The discrepancy between the two methods is only one per cent. 



b. Method of Zuntz and Schumberg (6). In their study of the meta- 

 bolism of a marching soldier Zuntz and Schumberg developed a somewhat 

 different method of calculation based, however, upon essentially the same 

 principles as the method of Kauffmann. All calculations are on the basis of 

 one hour. 



The N in the Urine (per hour) (a)X2.56 = C from protein in the res- 

 piration. 



The CO 2 output in grams per hour X 3/11 C output in grams per hour. 

 The C of respiration C of protein in respiration = C of carbohydrate 



and fat in respiration (b). 



N in urine X 8.45 = O 2 from protein in respiration. 

 Total O 2 absorbed O 2 from protein = O 2 absorbed for carbohydrate and 



fat (c). 



The O 2 for oxidation of one gram of fat = 3.751 4 (average). 

 The O 2 for oxidation of one gram of CH = 2.651 (average). 

 Let X = number of grams C from fat (1 gm. C from fat == 12.3 Cal.). 

 Let y = number of grams C from CH (1 gm. C. from CH = 9.5 Cal.). 



x + y = b. (1 gm. N. from Prot. == 26.0 Cal.) 

 3.751 x + 2.651 y == c 



Solving for x and y, a X 26 = Cal. from Prot. 



x X 12.3 = Cal. from fat. 



y X 9.5 = Cal. from CH 



Total = Cal. per hour. 



4 Compare the thermal quotients ( see page 556 ) . 



