48 Numerical InflruSlions 



So that the Content is 314 Foot and above 

 a Qiiarter. 



A Semicircle and Quadrant, or any Seg- 

 ment of a Circle, are mcafur'd the fame Way 

 that a whole Circle is, viz. half the Diame- 

 ter, or Perpendicular^ by half the Compafs. 

 In the foregoing Circle, if you would know 

 the Content of that little Piece D C B. the 

 Arch D. B. is 78 Foot and a Half, the half of 

 it is 39 and a Quarter, which multiply'd by 

 100, the Semidiameter gives 5925 for the 

 Content, and fo cf a Quadrant, &c\ And 

 itmuft be noted that all thefe Figures are in 

 Ufe in Gardening:^ we break Circles, Semi- 

 circles, and Quadrants out of bur Squares, 

 for the greater Diverfity and Ornament there- 

 of 5 but, becaufe iC would be a Trouble to 

 find the Diameter ef the Segment of a Circle 

 at all Times, I ihail (hew i of 



How to find the Conteiit of the Segment of a 

 Circle^ without knomng the Diameter. 



Let E F G be the Segment ^ the Subtenfe, 

 or Chord-Line, is 170 Foot, the Perpendicu- 

 lar G H 50 Foot 5 now multiply 4- of the 

 one by the whole of the other, and the Pro- 

 duft will be the Content, 



The-f of 170 Foot is near 113, which 

 multiply'd by 50, produces 5650 fuperficial 

 Feet^ and that is the Content of that Segment, 

 Portion, or Part of a Circle. 



To 



