50 \^^:iJumerical InflruElions 



So that as 1.27 is to 50 the Length, fo 

 the Breadth 37 is 1456 Foot, the.Gontent. 



\the Reafon why I have^ in the Dividend of 

 thi^ Stiffly added two Cyphers^ is to make it e- 

 qual to the two FraBions in the Divifor 5 and 

 this I parti Gidarly advife the Reader of ^ be- 

 caufe he is noty perhaps^ very well jkiTd in De- 

 cimal Divijion of Feet and Parts^ by Feet and \ 

 Farts. But iif there had been five Figures in 

 the Fraftion of the Divifor, I fnould- likewife 

 have a^ded five Cyphei^s'' i-n the Dividend, to 

 balknceit. And thus much of circular Fi- 

 gures;-- ^— 



How to find the fuperficial Contervt of regular 

 Polygons^ as Pentagoni^ HexagonSy^Hepta- 



■ .r^-,d r n^iQ i\^ji . . 



Multiply half the Sum of the Sides by z 

 Perpendicular let fall from the Center upon 

 on^'of the Sides, and the Produd: will be the 

 Area^ or fuperficial Content of the Polygon. 



In the following, the Sides B C fuppofe to 

 be 84 Foot, the Sum of the Sides 5, the 

 Work will ftand thus : 



The Half of 420,: which is the Produd of 

 84 by 5, is 210 5 and this 210 multiply'd by 

 56 Foot, the Semi-diameter, or, as it is ge- 

 nerally here call'd, thq. Perpendicular, gives 

 11760 Square Foot for 'the Content thereof. 

 And this Way will mcafurc any Figure,letit be 



