/(?r G A R D E N E R S, SZC. 1^3 



20COOCOO, which I divide by 40 Chains no 

 Links, the limited Bafe 5 the Quotient is 50 

 Chains no Links, for the Height of the Per- 

 pendicular, as in this Figure; A B is the gi- 

 ven Bafe 40, upon any Part of which Bafe I 

 fet the Perpendicular 50, as at C ^ then the 

 Perpendicular is CD^ therefore I draw the 

 Lines D A, D B, which make the Triangle 

 D A B to contain juft ico Acres, as requir d : 

 Or if I had fet the Perpendicular at E, then 

 would E F have been the Perpendicular 50 5 

 and by drawing the Lines FAB, containing 

 100 Acres, the fame as D A B. If you con- 

 fider this well, when you are laying out a 

 new Piece of Land, of any given Content, in 

 any Place, although you in your Way want 

 100 Lines and Angles, yet you may, by ma- 

 king a Triangle to the firft Station you began 

 at, cut off any Qiaantity required. 



HoTV to find the Length of the 'Diameter of a 

 Circle^ which jhaU contain any Number of 

 Acres requird. 



Say, as 1 1 is to 14, fo will the Number of 

 Acres given be to the Square of the Diameter 

 pjf the Circle required. 



K 3 Msf ample. 



