162 TABLE 146. 



VOLUME OF PERFECT CASES. 



Values of 1 + . 00367 1. 



The quantity i + -00367 1 gives for a perfect gas the volume at t when the pressure 

 is kept constant, or the pressure at t when the volume is kept constant, in terms 

 of the volume or the pressure at o. 



(a) This part of the table gives the values of i -f- .00367 1 for values of t between o 

 and 10 C. by tenths of a degree. 



(b) This part gives the values of i + .00367 1 for values of t between 90 and + 1990 

 C. by 10 steps. 



These two parts serve to give any intermediate value to one tenth of a degree by a sim- 

 ple computation as follows : In the (b) table find the number corresponding to 

 the nearest lower temperature, and to this number add the decimal part of the 

 number in the (a) table which corresponds to the difference between the nearest 

 temperature in the (&) table and the actual temperature. For example, let the 

 temperature be 682.2 : 



We have for 680 in table (6) the number .... 3.49560 



And for 2.2 in table (a) the decimal .00807 



Hence the number for 682.2 is 3-50367 



(0) This part gives the logarithms of i + . 00367 /for values of t between 49 and 



+ 399 C. by degrees. 



(d) This part gives the logarithms of i -f .00367 1 for values of t between 400 and 1990 

 C. by 10 steps. 



(a) Values of 1 + . 00387* lor Values of * between and 10 0. by Tenths 

 of a Degree. 



SMITHSONIAN TABLES. 



