DISTURBING MAGNET BROADSIDE-ON. 27 



m 4- 1 . m + 3 46 2 

 2.4 ~? 



sum= 2 - (m + 1) . ^^+ (m + 1) (m + 3) ^ . 



The whole angular momentum 

 = 2aj&xa6x [2C-"- 1 + (m + l).^- 3 { - a 2 + (m + 2) . 6 2 )], 



or = 4a/3 x a6 x [c^ 1 + ^ . c 3 { - a 2 + (m + 2) . 



15. /ft ^A^ same arrangement, to find the tendency of 

 the action of A. to produce a motion of 'translation of 'B. 



It is obvious that there is no tendency to carry B to 

 or from A. But there is a tendency to carry it to the 

 right. The forces on the two poles of B are the same 

 as those just found, but that on the blue pole must be 

 subtracted from that on the red pole. The efficient 

 force therefore is 



Expanding as before, this becomes 



2 J c/3xa.cf fn - 1 x2(m + l)- 



c 



