PRINCIPLES OF FEEDING. 141 



ter, 20 pounds; j)roleiii, 1.5; carbohydrates, 9.5 pounds; 

 ether extract, 0.4 pounds, and the nutritive ratio, i: 7. 



All that is necessary is to find sucli a combination of 

 foods as will make a nutritive ratio of 1:7 and furnish 

 approximately 20 pounds of dry nuitter. For a trial 

 ration, assume 15 pounds of red clover hay and 10 pounds 

 of oats. 



First Trial. — Required to find the number of pounds 

 of dry matter, protein, carbohydrates, and ether extract, 

 respectively, in 15 pounds of clover hay and 10 pounds 

 of oats. 



(a) In 100 pounds of clover hay there are, according 

 to the table, 84.7 pounds of dry matter, 6.8 pounds of 

 protein, 35 8 pounds of carbohydrates, and 1.7 pounds 

 of ether extract. 



Then in 15 pounds of clover hay there are: 



15 X -,^„r = 12.7 of dry matter; 



15 X 7,1^7 = I.02 pounds of protein; 



i5X^= 5.37 pounds of carboh3fdrates; and 



15 X ,'oi7 = -25 pounds of ether extract. 



ij)) In 100 pounds of oats there are, according to the 

 table, 89 pounds of dry matter, 9.2 pounds of protein, 

 47.3 pounds of carbohydrates, and 4.2 pounds of ether 

 extract. 



Then in 10 pounds of oats there are: 



10X^ = 8.9 pounds of dry matter; 

 ioX-^= .92 pounds of protein; 

 10 x-^^ — 4-73 pounds of carbohydrates; and 

 10 X -~ = 4.2 pounds of ether extract. 



Adding the amounts of these different substances con- 

 tained in: 



