INDUCTION IN AN OPEN CIRCUIT. 525 



is not absolute, and that the resistance of the dielectric, instead 

 of being infinite, is represented by R r The latter equation should 

 then be replaced by 



from which follows 



R'WV i /R' \ 

 ^ + L 7 / ^l/OVR^ V 



This equation is the same as equation (19), and has an integral 

 of the form V = Ke^ + AW. If the roots of the quadratic equation 

 analogous to equation (21), which determines the coefficients p and 

 /o', are imaginary, as, for the most part, will be the case unless the 

 resistance R x of the dielectric is very small, the potential V is 

 represented by a periodical function of decreasing amplitude. The 

 value of the period is (538) 



27T 



~7 = rr~/R' 



The constants of the general integral will be defined by the 

 condition that for /=0 we have V = and I' =11. Putting 



i R' 



a = + , we thus get 

 t^-Kj JL 



I', f? 



V = -e * sin a/. 

 C 



On the other hand, the initial intensity IJ of the induced 

 current is given as a function of the inducing current I (542) 

 by an equation (33) in which the resistance of the circuit does 

 not enter. We get then, by substitution, 



M _? 

 V = I CLV^ 



M T _ 



We may control this result by connecting the ends of the wire 

 at a given period, and for a very short time, with the binding screws 



