by twenty to change it to a ton basis. The sum of these values will 

 give the total approximate value of the fertilizer per ton at the prin- 

 cipal places of distribution. 



Example : — Supposing a fertilizer shows the following analysis : 



Nitrogen, 2.5^ 



Soluble Phosphoric acid, 6.5 



Reverted " " 3.5 



Insoluble " " 1.6 



*Potassium oxide, (as sulphate), 8.4 



2.5 pounds nitrogen at 20^ cents^5i.25 cents x 20= $10.25 



6.5 pounds soluble phosphoric acid at 5 cents=32.5 cents x 20^6.50 



3.5 pounds reverted phosphoric acid at 4.5 cents=:i5.75 



cents X 20= 3.15 



1.6 pounds insoluble phosphoric acid at 2 cents=:3.2 cents X2o=.64 

 8.4 pounds potassium oxide at 5 cents=42 cents x 20^ 8.40 



Value per ton, $28.94 



In case of bone and tankage, we calculate separately the nitrogen 

 and phosporic acid value of each grade of mechanical fineness by 

 multiplying the pounds of nitrogen and phosphoric acid per ton by 

 the per cent, of each grade, and multiplying these products by the 

 trade values per pound, of nitogen and phosphoric acid in each 

 grade, and express the final product in cents. Adding the separate 

 values of each grade of both ingredients, we have the valuation of 

 the material in question. 



Example : — Supposing a bone shows the following analysis : 



Nitrogen, 2.5^ 



Total phosphoric acid, 22.5^ 



*Tlie term " potassium oxide" in this bulletin designates the compound now generally 

 known as potash in agricultural literature. 



Wm. p. Brooks, Director. 



