August 1, 1889.] 



KNOWLEDGE 



215 



fourth-best club, and exposing the hand witli .-dl the trumps against, 

 and B therefore leads the smallest. 



Trick 7. 

 A 





 0% 



B 

 Tricks— A B, I ; Y Z, 3. 



Note. — B wins A's queen of clubs, the only chance being that 

 Y and Z may each hold another club. If A remains with the lead, 

 he must continue with a spade ; Y of course trumps, and Z discards 

 his losing club, and wins all the remaining tricks. 



Tricks— A B, 6 ; Y Z, 3. 



YZ win the remaining tricks, and score the odd trick and two liy 

 honours, and 



AB SAVE THE Game. 

 A's Hand. B's Hand. Y's Hand. Z's Hand. 



H.— 9, 8. H.— Kg, 7. H.— Ace, Kn, 3. H.— Qn, 10, 6,5, 



S.— Ace, 10, 9, 7, S.— Kg, Q, 3. S.— 8, 4. 1,2. 



6, 5, 2. D.— 6, 4, 3. D.— Kn, 9, 7, 5, S.— Kn. 



D.— Ace, Kg. C— Kg, 10, 8, 5, 2. D.— Qn, 10, 8. 



C— Qn, Kn. 3. , C— Ace, 7, G. C— 9, i, 2. 



Bemarlts. — At Trick 7 A leads the ace of diamonds, as, if he keeps 

 a card with which he can get the lead when he has only spades left, 

 he must lose the game. 



If, at Trick 2, A leads the deuce of spades, as was the practice before 

 the introduction of American leads, AB lose the game, for the 

 reason that B cannot place the spade suit. In that case, at Trick 5, 

 B will lead the khig of spades to force the strong trump hand. In 

 this he will succeed ; but he will also enable Y to discard a club. 

 Z, following this indication of Y's suit, will lead the queen of 

 diamonds ; A winning with the king of diamonds will continue with 

 the queen of clubs, to which Y will play the ace ; and whether Y 

 leads diamonds or clubs, A B will not be able to make more than 

 five tricks, and will therefore lose the game. 



On the other hand, it may be pointed out that Z affords B 

 valuable information as to the position of the trumps by his play 

 at Tricks 2, 3, and 4. It so often happens that such information is 

 useful in playing a defensive game that some good players are 

 opposed on this account to the extension of the American code to 

 the trump suit. 



Elementary Explanation op the Play. 



Trlcli 1. — A opens his longest suit and leads the ace, which is the 

 correct play when holding four or more others. Y, B, and Z play 

 their smallest spades. 



Trick 2. — A rightly continues his suit so as to clear it if possible. 

 He is not deterred by the fall of the knave, for Z may have both 

 king and queen, and in any case A is too weak to lead trumps. As 

 things turn out, he forces a trump from the strong trump hand, 

 although Z is so rich in them that it makes no difference to him. 

 Note that the king of spades after this trick is marked in B's 

 hand. 



'IHfk 3.— Having still five trumps to the queen left, Z leads a 

 small one ; excepting the queen of diamonds he has no plain cards 

 of his own to protect, but he plays to save any good cards his 

 partner may hold from falling to a hostile " rufV." Y of course 

 plays the ace, so as to ensure a second round. 



THoh 4. — Y follows the almost invariable rule to return a 

 partner's trump lead at the first opportunity, and, as lie has 

 only two o£ the suit remaining, he rightly loads the higher of 



them. With knave and two others left, he would return the 

 lowest. Z plays the 6 to show that he has it, for his partner knows 

 that he has the deuce as it was the turn-up card. 



Trick 5. — B having reason to think that by continuing his 

 partner's suit he will enable one adversary to trump and the other 

 to discard, determines to open his own long suit. A, as third 

 player, having two cards in sequence, plays the lower one ; B now 

 knows that the queen is with A or Z, since Y has to win knave with 

 ace ; but if A had played the queen, there would have been no 

 evidence at all as to the whereabouts of the knave. 



Trick 6. — Y opens his longest suit. 



Trick 7. — Ordinaril}' A should retain as long as possible the 

 command of his adversary's suit ; but, as has already been ex- 

 plained, there is a special reason for his disposing of any card that 

 would put the lead into his hand later on. Therefore he leads out 

 his ace of diamonds. 



Trick 8. — The queen and knave of clubs being played, the king 

 and 10 are of equal value. B knows that his partner has no more 

 clubs (for he has all the remaining spades), and he wins the queen, 

 as the only chance of making another trick in the suit, and so 

 saving tlie game. 



Cfteesi Column* 



By I, GUNSBEEG (MEnilSTO). 



[Contributions of general interest to chess players are invited. 

 Mr. Gunsberg will be pleased to give his opinion on any matter 

 submitted for his decision.] 



PBOBLEM BY IIERR EICHSTADT. 

 Black. 



White to play and mate in three moves. 

 White, seven pieces ; Black, five pieces. 



J. 



Game played Jlay 2, in the New York Tourna 

 Ieregulau Opening. 

 Black. WurrK. 



I. IJuiisberg. I J. M. Hnulmm. 

 P to Q4 24. B to Kt4 



P to KKt3 (J) 2.5. B to R4 

 B to Kt2 ' 20. B to B2 



P to Kt3 27. B to K2 



B to Kt2 28. BP X P 



Kt to Q2 (rf) 29. P X P 



WiiiTn. 

 5L Ilanb.im. 

 r to Q4 

 PtoKB4(«) 

 P to K3 

 B to (J3 

 P to B3 (f) 

 Kt to B3 

 QKt to Q2 

 Castles 

 Kt to Kt5 

 Pv to B2 

 Kt to Esq 

 Kt to Kt3 

 B to Q2 (j) 

 B to Ksq 

 11 to QBsq 

 KR to B2 

 KttoBsq(i) 

 Kt to R3 

 B to B2 

 B to K2 

 P to QKt3 

 Px P 

 P to QKt4 



KKt to B3 

 t'astles («) 

 P to K3 

 Kt to Ksq 

 Kt to Q3 (/) 

 P to QB4 ! 

 Q toK2(/() 

 QR to Bsq 

 R to B2 

 KR to B.sq 

 P to R3 

 P to K4 ( /) 

 P to Bo (k) 

 B to B3 (0 

 PxP 



PtoQKt4()») 

 Kt to Kt3 



30. Kt to B4 



31. B to B3 



32. KtxB 



33. Q to Q3 



34. Kt to Q2 



35. KttoKtsqO 



36. P to K4 



37. BxP 



38. Q to B3 



39. Q to K2 



40. B to B5 



41. Q X P 



42. PxKt 



43. B to B3 ((■) 



44. K to R,sq 



45. Q to Bsq 

 Resigns 



raout. 



Black. 

 I. Gunsberg. 

 B to Q2 

 Kt to R4 («■) 

 P to KK4 («) 

 Kt toQ3(y;) 

 PxP 

 BxP 

 QtoB2(y) 

 B toK3 

 QxKt 

 K to Kt2 

 Kt(Q3) to B5 (r) 

 B to B3 

 PxP 

 RtoQ2 

 Kt to K4 

 Kt to Kto 

 Kt to R5 (0 

 KtxB 



R(Bsq)toQsq(«) 

 Q to K6 (ch) («•) 

 R to QS (ch) 

 Q to B5 



