12 THE TABLES: EXPLANATORY 



VIII; add the two weights together and divide by two, 

 and the normal weight for an individual of the observed 

 trunk-length and chest-circumference will have been 

 obtained. The weight derived from the Tables is now 

 compared with the actual weight observed, and the per- 

 centage deviation above or below the normal is readily 

 calculated. The figure derived from the Tables should 

 always be taken as equal to 100 per cent. 



If the individual represents an average type, the two 

 weights obtained from the two measurements will be 

 found practically identical; thus: 



EXAMPLE Metric System 



FEMALE, AGE 10 YEARS 



[ Weight of the body = 34-0 kilograms 



Observations < Length of the trunk =72-7 centimetres 



[ Circumference of the chest = 64 centimetres 



CALCULATION 

 Weight derived from length of the trunk (72-7 cm.) = 34-15 



kilos (from Table VII.). 

 Weight derived from circumference of the chest (64-0 cm.) 



= 33-84 kilos (from Table VIII.) . 



. . 34-15 + 33 84 



Averaging - ~ = 34-0 kilos, which is the normal 



weight corresponding to the observed length of the trunk 

 and the circumference of the chest. 



Subtracting the calculated from the observed weight, 

 34 - 34 = 0. 



Therefore the person weighs exactly what she should weigh 

 according to the Tables. 



EXAMPLE American Standard System 



FEMALE, AGE 10 YEARS 



f Weight of the body = 74 Ib. 15 oz. 



Observations < Length of the trunk =28% inches. 



1 Circumference of the chest = 2534 inches 



