THE TABLES: EXPLANATORY 13 



CALCULATION 



Weight derived from length of the trunk (28^ in.) = 



75-32 Ib. (from Table XIX.) 

 Weight derived from circumference of the chest (25^ in.) 



= 75-17 Ib. (from Table XX.). 



. 75-32 + 75-17 

 Averaging - ~ = 75-25 Ib., which is the normal 



weight corresponding to the observed length of the trunk 



and the circumference of the chest. 

 Subtracting the calculated from the observed weight, 



74-94 - 75-25 = -0-31 Ib. 



-0-31 X 100 *- 75-25 = -041%. 



Therefore the person weighs 0'41 per cent, less than she should 

 weigh according to the Tables. 



If, on the other hand, the circumference of the chest 

 and the length of the trunk are markedly out of pro- 

 portion to each other, the weight obtained from either 

 the one or the other may be very considerably above or 

 below the actual weight found, although by taking the 

 two figures together as mentioned above the indi- 

 vidual will be found to have an absolutely normal weight ; 

 thus : - 



EXAMPLE Metric System 



MALE, AGE 27 YEARS 



f Weight of the body = 100-5 kilograms 



Observations < Length of the trunk = 100-0 centimetres 



1 Circumference of the chest = 105-5 centimetres 



CALCULATION 



Weight derived from length of the trunk (100-0 cm.) = 



89-78 kilos (from Table I.). 

 Weight derived from circumference of the chest (105-5 cm.) 



= 112-81 kilos (from Table II.). 



8978+112-81 

 Averaging - ~ ~ = 101-3 kilos, which is the nor- 



