14 THE TABLES: EXPLANATORY 



mal weight corresponding to the observed length of the 

 trunk and the circumference of the chest. 



Subtracting the calculated from the observed weight, 

 100-5 - 101-3 = -0-8 kilos. 

 -08 X 100 -5- 101 3 = - 0-79%. 



Therefore the person weighs 0-79 per cent, less than he 

 should weigh according to the Tables. 



EXAMPLE American Standard System 



MALE, AGE 27 YEARS 



f Weight of the body = 221 Ib. 9 oz. 



Observations < Length of the trunk = 39% in. 



1 Circumference of the chest = 41^ in. 



CALCULATION 



Weight derived from length of the trunk (39% in.) = 198-02 



Ib. (from Table XIII.) . 

 Weight derived from circumference of the chest (41^ in.) = 



248-13 Ib. (from Table XIV.). 



198-02 I 248-13 



Averaging - - = 223-08 Ib., which is the nor- 

 mal weight corresponding to the observed length of the 

 trunk and the circumference of the chest. 



Subtracting the calculated from the observed weight, 

 221-56 - 223-08 - -1'52 Ib. 

 -1-52 X 100 -;- 22308 = -0-68%. 



Therefore the person weighs 0-68 per cent, icss than he should 

 weigh according to the Tables. 



DIFFICULTIES IN TAKING MEASUREMENTS. It should 

 be noted that the calculated weights derived from chest- 

 measurements show greater individual variations than 

 those obtained from trunk lengths. This is more par- 

 ticularly marked in the adult female owing to the diffi- 



