October 1, 1894.] 



KNOWLEDGE 



239 



earth 229,260 miles). At 6h. 8m. p.m. on October 7th 

 the 5th magnitude star A Sagittarii will disappear at an 

 angle of 1°, and reappear at 7h. Im. p.ji. at an angle of 

 323°. At 7h. 14m. p.m. on the lOtb the 6th magnitude 

 star .50 Aquarii will disappear at an angle of 80°, and 

 reappear at 8h. 25m. p.m. at an angle of 264° ; and at 

 llh. 11m. P.M. the 6i magnitude star B.A.C. 7H35 will 

 disappear at an angle of 102°, and reappear at llh. 58m. 

 P.M. at an angle of 186°. At 2h. 45m. a.m. on the 15th 

 the 6th magnitude star it Piseium will disappear at an 

 angle of 36°, and reappear at 3h. 47m. a.m at an angle 

 of 266°; and at 5h. 5Bm. p.m. the 6th magnitude star 

 19 Arietis will disappear at an angle of 113\ and reappear 

 at 6h. 27m. p.m. at an angle of 193°. At 4h. 13m. x.si. on 

 the 16th the 6th magnitude star 27 Arietis will disappear 

 at an angle of 115°, and reappear at 4h. 58m. a.m. at 

 an angle of 202°. At 5h. 27m. a.m. on the 17th the 

 6i magnitude star 66 Arietis will disappear at an angle of 

 73°, and reappear at 6h. 31m. a.m. at an angle of 260°. 

 At 3h. 5m. a.m. on the 18th the 5i magnitude star y} Tauri 

 will make a near approach at an angle of 165°. At 

 Ob. 34m. A.M. on the 18th the 6^ magnitude star B.A.C. 

 1648 will disappear at an angle of 45°, and reappear at 

 lb. 33m. A.M. at an angle of 289°. At 5h. 15m. a.m. on 

 the 20th the 5^ magnitude star 59 Aurigs will disappear at 

 an angle of 93", and reappear at 6h. 29m. a.m. at an angle 

 of 282°. 



<!^C9S Column. 



By 0. D. LooooK, B. A. Oxen. 



CoMMTJNiOATioNs for tMs columii should be addressed to 

 C. D. LococK, Burwash, Sussex, and posted on or before 

 the 12th of each month. 



Solutions of September Probhms (F. H. Guest). 



No. 1.— B to Q7. 



Solved also by 1. K to Kt5. 



Correct Solutions received from Chat and Crossgar 



(both solutions) ; J. E. Gore, W. H. Skelton, H. S. 



Brandreth, W. Willby. 



No. 2.— Kt to Kt6. 

 Correct Solution received from Chat, W. Willby. 



Additional solution of -July Problem No. 1 received 

 from E. Boustead. 



W. H. Skeltoti.— In No. 2, after 1. B to Kt3, P to Kt5, 

 2. Kt to K6ch, K to B 3, there is no mate. 



A. (t. Fellows. — The family success in Boys Tournament 

 is remarkable. We shall be glad to receive the problem 

 composed with the Knowledge Prize set of men. 



J. E. (rorc. — Probably the diagrams you require could 

 be obtained from the British Chess Company, 247, High 

 Holborn. They usually cost about Is. a hundred. Your 

 last two problems sulier from the same evils of over- 

 crowding and want of economy. No. 1 is quite spoilt by 

 the ilouhli' threat, which is only allowable when Black is 

 compelled to avoid one of the threatened mates. The mates 

 in tills are also of little beauty, and some of the Pawns 

 unnecessary. The other has two good mates with the 

 Queen, but the problem would be much improved if you 

 could abolish the Black Queen with its attendant Pawns, 

 and also the Pawn at K7. It is not a bad plan for inex- 

 perienced composers to limit themselves to twelve or, at 

 any rate, sixteen pieces. The best problems seldom have 

 more. 



ir. Willby. — The key is still weak, in that it moves a 



piece which is en prise, thereby depriving the Black King 

 of half his liberty. Moreover, there is a bad dual after 

 1. . . P to K6, and also after several moves of the Black 

 Queen. This last piece should be got rid of, as it leads to 

 no fresh mate. It should be possible to get the four 

 variations which you aim at by employing ten or, at most, 

 twelve pieces. 



R. Kelh/. — Thanks for the problems. We shall be glad 

 to insert the block problem in the November number. The 

 three threat problems do not seem very happily constructed 

 as regards economy of force. Many of the pieces do 

 scarcely any work. 



PROBLEM. 

 By B. G. Laws. 



Black (5). 





a^ 



^'mm^- 



mm. mm, wb-% 



Sp P^'P^^P 



White (8). 



White mates in three moves. 



CONDITIONAL PROBLEM. 

 By W. De Morgan. 



Black (5). 



White (7). 



White mates in three moves. 



[On condition that when a Rook moves it becomes a 

 Knight, and rice rersa.\ 



The following game was played in the fifth round of the 

 Leipsic International Tournament, between M. -Janowsky, 

 of Paris, and Mr. R. Teichmann, of London. 



"French Defence." 

 Whitb Black 



(M. .lanowskr). (Mr. Teichmann). 



1. P to K'4 1. Pto K3 



2. P to Q4 2. P to Q4 



3. Kt to QB3 3. Kt to KB3 



4. B to Kt5 4. B to K2 



5. P to K5 5. KKt to Q2 



6. BxB 6. QxB 



