464 GOLD, PLATINUM, PALLADIUM, &C. 



It is obvious that the O25 grain of loss, over and 

 above this integrant particle of sal-ammoniac, 

 must have been water. Now, the 4*625 grains 

 of muriatic acid, in the 6 '75 grains of sal-ammo- 

 niac volatilized, must have existed in the 28 '625 

 grains of the soda-muriate of rhodium, and must 

 have been in combination with the oxide of 

 rhodium. 



From the preceding analysis it appears, that 

 soda-muriate of rhodium is a compound of 



Yellow oxide of rhodium 7-5 



Muriatic acid . . 4-625 



Common salt . 7-5 



Water 9-0 



28-625 



Atom of Now, this salt is perfectly neutral : 9 re- 

 peroxide of J 

 rhodium, presents eight atoms or water ; 7'5 is an inte- 

 grant particle of chloride of sodium ; and 4-625 

 an integrant particle of muriatic acid. 7%5 there- 

 fore, must represent the weight of an integrant 

 particle of yellow oxide of rhodium. The con- 

 stituents of the soda-muriate of rhodium may 

 therefore be represented as follows : 



1 atom permuriate of rhodium 12'125 

 1 atom muriate of soda . 8 '62 5 



7 atoms water . . 7*875 



28-625 



For one of the atoms of water separated by heat, 



