CH. IX CENTRIFUGAL FORCE 141 



The formula for the centrifugal force being 

 : CF ; with a weight of 2300 pounds and a 



2,2.21- 



radius of 50 feet, we find, corresponding to different 



velocities, the following centrifugal forces : — 



At 7 miles an hour, v = 10.30 ft. per sec, CF = 15 1.5 pds. 

 10 ,, ,, 7'= 14.66 ,, ,, CF == 307.0 ,, 



15 ,, ,, 7/ = 22.00 ,, ,, CF==69i.4 ,, 



With a weight of 4000 pounds, 



At 7 miles an hour, v = 10.30 ft. per sec, CF = 263.6 pds. 

 10 ,, ,, t= 14.66 ,, ,, CF= 534.0 ,, 



15 ,, ,, 7'= 22.00 ,, ,, CF = 1202.0 ,, 



In an empty coach weighing 2300 pounds, the 

 centre of gravity is 4 feet from the ground. 



The weight, 2300, will act at the end of an arm 

 AB, Fig. 71, 2.5 feet long, with an effect of 5750 

 pounds (2300 X 2.5 = 5750) holding the coach 

 down ; the centrifugal force corresponding to a 

 speed of seven miles an hour, 151.5 pounds, will act 

 at the end of the arm BG, 4 feet long, with an effect 

 of 606 pounds (15 1.5 : 4 = 606) tending to over- 

 turn the coach. 



At different speeds, the forces will be as follows : — 



FOR THE UNLOADED COACH. 



At 7 miles an hour, 1 5 1 . 5 X 4 = 606 pounds. I 

 10 ,, ,, 307.0x4=1228 ,, £ 



15 .- .- 691.4X4 = 2765 ,, J 



