310 ARITHMETIC 



CARPETING 



Carpet is made in various widths. Ingrain carpet is usually 

 36 in., or 1 yd., wide; Brussels carpet is 27 in., or f yd., wide. 

 Carpet borders are 22 in., or f yd., wide. A linear yard of 

 ingrain carpet contains 1 sq. yd., and a linear yard of Brussels 

 carpet contains f sq. yd. 



Rule. To find the number of linear yards of carpet required 

 for a room, if no allowance is made for cutting and matching 

 the strips, divide the area of the room in square yards by the area 

 of a linear yard .of ihe carpet. 



EXAMPLE. How many yards of Brussels carpet will be 

 required to cover a floor 36 ft. long and 21 ft. wide, 

 making no allowance for cutting and matching? 



SOLUTION. Area of floor = 36X21 = 756 sq. ft. = ^~ 



= 84 sq. yd.. A linear yard of Brussels carpet has an area of 

 sq. yd. Hence, the number of linear yards required is 

 84-H=112 yd. 



In practice, there is usually considerable loss due to 

 cutting and matching. To find the number of yards re- 

 quired for a room, when allowance is made for loss, the 

 width of the room is divided by the width of a single 

 strip. The quotient is the number of strips required, 

 supposing them to run lengthwise of the room. The 

 number of strips multiplied by the length in yards of a 

 single strip, making allowance for the loss required for 

 matching, is the number of linear yards required. 



EXAMPLE. How many yards of Brussels carpet will be 

 required to cover a room 23 ft. long and 15 ft. wide, 

 making an allowance of 1 ft. on each strip for matching? 

 The carpet is supposed to run lengthwise. 



SOLUTION. Width of room =15 ft. = 180 in. Width of 

 carpet = 27 in. Number of strips 180-4-27 = 6f. Hence, 

 7 strips must be used, the excess, 9 in., being cut off or turned 

 under. Allowing 1 ft. for matching, length of strip = 23 -f-1 

 = 24 ft. = 8 yd. Number of linear yards required = 7X8 

 = 56 yd. 



